Dear Reader, Below are easy aptitude questions of kind which could help you to practice for TCS and other similar papers.
Question 1
Ramesh Khanna was five times old as his son Kishan Khanna eight years ago. Now he is three times as old as his son Kishan Khanna. Assume they both live in a country where people understand only binary numbers and they use symbol '0' for binary 1 and '1' for binary zero. Also they add 1 before any binary number. Express Ramesh Khanna’s present age in accordance to that world
a) 1001111 b) 1001111 c) 1100011 d) 1010000
Answer : a) 1001111
Solution :
Let Ramesh Khanna’s age be represented as ‘F’ eight years ago and the age of Kishan Khanna be represented as ‘S”.
F = 5 S
F + 8 = 3 (S + 8)
5S + 8 = 3S + 24
5S – 3 S = 24 – 8
2S = 16
S = 8
F = 5 S
F + 8 = 3 (S + 8)
5S + 8 = 3S + 24
5S – 3 S = 24 – 8
2S = 16
S = 8
Now Ramesh Khanna’s age will be 5S + 8 = (5x8) + 8 = 48
Expressed as binary 110000 . However the people in their country use symbol 0 for binary one and 1 for binary zero. Replacing 1 with 0 and 0 with 1 we get 001111. Also those people usually add 1 before any binary number. Hence the answer becomes 1001111.
Expressed as binary 110000 . However the people in their country use symbol 0 for binary one and 1 for binary zero. Replacing 1 with 0 and 0 with 1 we get 001111. Also those people usually add 1 before any binary number. Hence the answer becomes 1001111.
Question 2
Bhavna is presently three times as old as her daughter Anushka. Ten years ago Bhavna was five times as old as her daughter Anushka was. After how many years, sum of their ages will be 100.
a) 10 b) 20 c)15 d) none of these.
Answer : a) 10
Solution :
Let Bhavna’s present age be represented as B
Let her daughter Anushka’s age be represented as A.
B = 3 A
Ten years ago,
B - 10 = 5(A – 10)
3A - 10 = 5A - 50
-10 + 50 = 5A – 3A = 2 A
40 = 2 A
A = 20.
B = 3 x A = 60.
Present sum of their ages = A + B = 80.
When 10 is added to both A and B, Sum of their ages will become 100. Hence, after 10 years, their sum of ages will be 100.
Let her daughter Anushka’s age be represented as A.
B = 3 A
Ten years ago,
B - 10 = 5(A – 10)
3A - 10 = 5A - 50
-10 + 50 = 5A – 3A = 2 A
40 = 2 A
A = 20.
B = 3 x A = 60.
Present sum of their ages = A + B = 80.
When 10 is added to both A and B, Sum of their ages will become 100. Hence, after 10 years, their sum of ages will be 100.
Question 3
Monisha was seven times as old as her daughter Mercy eight years ago. Now three times Mercy’s age is her mother age. Before how many years the ratio of their ages (ratio of mother's age to Mercy's age) will be increased by 1 from the current ratio
a) 5 b) 4 c) 8 d) none of these.
Answer : b) 4
Solution :
Eight years ago -- let Monisha’s age be M and Mercy’s age be D.
M = 7 D
Now M + 8 = 3 (D + 8)
7 D + 8 = 3D + 24
7D - 3 D = 24 - 8 = 16
D = 4 = age of Mercy before 8 years
M = 28 = age of Mother before 8 years
M = 7 D
Now M + 8 = 3 (D + 8)
7 D + 8 = 3D + 24
7D - 3 D = 24 - 8 = 16
D = 4 = age of Mercy before 8 years
M = 28 = age of Mother before 8 years
Current age of Mercy = D + 8 = 12
Current age of Monisha = M + 8 = 36
Current ratio of mother's age to Mercy's age = 36/12 = 3.
Let before x years this ratio becomes 1 more than the current ratio. i.e x denotes the number of years before which the ratio becomes 3 + 1 = 4.
Then 36 - x / 12 - x = 4
36 - x = 48 - 4x
3x = 12
Or x = 4
i.e before 4 years, the ratio of their ages will be 4. Therefore answer = 4
Current age of Monisha = M + 8 = 36
Current ratio of mother's age to Mercy's age = 36/12 = 3.
Let before x years this ratio becomes 1 more than the current ratio. i.e x denotes the number of years before which the ratio becomes 3 + 1 = 4.
Then 36 - x / 12 - x = 4
36 - x = 48 - 4x
3x = 12
Or x = 4
i.e before 4 years, the ratio of their ages will be 4. Therefore answer = 4
